2x^2+4=5x-7

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Solution for 2x^2+4=5x-7 equation: 



2x^2+4=5x-7

We move all terms to the left:

2x^2+4-(5x-7)=0

We get rid of parentheses

2x^2-5x+7+4=0

We add all the numbers together, and all the variables

2x^2-5x+11=0

a = 2; b = -5; c = +11;
Δ = b2-4ac
Δ = -52-4·2·11
Δ = -63
Delta is less than zero, so there is no solution for the equation

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